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VII.22.(VIII.9) Descompunuri in factori

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1. x³ - 5x %2b6 = #
invite students , multiple choice questions ,
2. DESCOMPUNERI IN FACTORI ATENTIE: 1.Pentru tastarea rezultatelor,daca aveti produsul a doua paranteze, una cu %2b si alta cu -, tastati mai intai pe cea cu %2b: DECI tastati (x%2by)(x-y), Nu (x-y)(x%2by) 2. Pentru tastarea rezultatelor,daca aveti produsul a doua paranteze, ambele cu aceeasi operatie, tastati mai intai paranteza care are o constanta mai mica in valoare absoluta: DECI tastati (x-4)(x-5) sau (x%2b5)(x%2b8) 3.Pentru x³ tastati x^2 4. Pentru radical din 3 tastati V3
(x%2bm)(x-m), , ,
3. (x %2b 1)(3x %2b 2) %2b (x %2b 1)(x - 5) = #
(a%2b2)(a-2), , ,
4. x³ %2b 6x %2b 9 = #
(3a%2b1)(3a-1), , ,
5. x¹º - 81 = #
(x%2b5)(x-5), , ,
6. x³ %2b 4x - 21 = #
(4x-y)(2x%2by), , ,
7. (x - 1)³ - 25 = #
(x^5%2b9)(x^5-9), , ,
8. (x - 2)³ %2b (x - 2)(x - 3) = #
(x%2b3)^2, , ,
9. x³ - m³ = #
(x - 5)^2, , ,
10. 4x³ - 4xy - 8y³ = #
(2x - 3y)^2, , ,
11. 9x³ - (x - y)³ = #
(a %2b 4)^2, , ,
12. Descompuneti in factori urmatoarele expresii:
(x-2)(x-3), , ,
13. 3(x - 1)³ - (2x - 2)(x %2b 1) = #
(x%2b4)(x-3), , ,
14. x³ - 5 = #
(x%2b7)(x-3), , ,
15. (2x - 3 )(x - 1) - (2x - 3)(2x - 6) = #
(2x%2b2y)(2x-4y), , ,
16. x³ %2b x - 12 = #
(3x-1)(-x%2b1), , ,
17. x³ - (4x³ - 4x %2b1) = #
(x%2b4)(x-6), , ,
18. x³ - 10x %2b 25 = #
(x%2b1)(4x-3), , ,
19. 4x³ - 12xy %2b 9y³ = #
(2x - 3)(2x - 7), , ,
20. a³ - 4 = #
(x-2)(2x-5), , ,
21. a³ %2b 8a %2b 16 = #
(x-1)(x-5), , ,